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(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{en}}{\epsilon_0}$,where $q_{en}$ is

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Zero

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(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{en}}{\epsilon_0}$,where $q_{en}$ is the net charge enclosed by the surface.From the figure,the Gaussian surface encloses two charges. Based on the problem description,these are a $+1$ charge and a $-1$ charge.Therefore,the net enclosed charge is $q_{en} = (+1) + (-1) = 0$.Substituting this into Gauss's Law,we get $\phi = \frac{0}{\epsilon_0} = 0$.Thus,the total electric flux through the spherical Gaussian surface is zero.

The figure shows the electric field lines of three charges with charges $+1, +1$,and $-1$. The Gaussian surface in the figure is a sphere containing two of the charges. The total electric flux through the spherical Gaussian surface is

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